Answer:
Attention! the "x" variable was missing in your typed question, but I am assuming that the actual function was defined by: [tex]y=-\frac{2}{3} x+7[/tex]
Table:
[tex]\left[\begin{array}{cc}x & y\\-12&15\\-6&11\\3&5\\15&-3\end{array}\right][/tex]
Step-by-step explanation:
In order to complete the requested table, we need to evaluate "y" for the four given values of the "x" variable in the Domain: {-12. -6, 3, 15}
Evaluation:
[tex]y=-\frac{2}{3} x+7\\y=-\frac{2}{3} (-12)+7=8+7=15[/tex]
[tex]y=-\frac{2}{3} x+7\\y=-\frac{2}{3} (-6)+7=4+7=11[/tex]
[tex]y=-\frac{2}{3} x+7\\y=-\frac{2}{3} (3)+7=-2+7=5[/tex]
[tex]y=-\frac{2}{3} x+7\\y=-\frac{2}{3} (15)+7=-10+7=-3[/tex]
The table therefore will be:
[tex]\left[\begin{array}{cc}x & y\\-12&15\\-6&11\\3&5\\15&-3\end{array}\right][/tex]