Question

anyone can give me the correct answer for me please. Actually I just want to check my answer wrong or what ! Thanks ✨✨(sorry for the photo )​

Answer 1

Answer:

[tex]x+y+3=0[/tex] and the point (-10,7) lies on the line.

Step-by-step explanation:

Given that the straight line passes through (-6,3) and (2,-5).

a)

So formula for finding out the line passing through two points (x1,y1) and (x2,y2) is

$(y-y1)=\frac{y2-y1}{x2-x1}*(x-x1)$

In the given question (x1,y1) and (x2,y2) are  (-6,3) and (2,-5).

So the equation of line would be

$(y-3)=\frac{-5-3}{2+6}*(x+6)$

$x+y+3=0$

b)

Given a point (-10,7)

by susbtituting in the equation we get

$-10+7+3=0$

As the point satisfies it lies on the line.