Answer:
[tex]x+y+3=0[/tex] and the point (-10,7) lies on the line.
Step-by-step explanation:
Given that the straight line passes through (-6,3) and (2,-5).
a)
So formula for finding out the line passing through two points (x1,y1) and (x2,y2) is
[tex](y-y1)=\frac{y2-y1}{x2-x1}*(x-x1)[/tex]
In the given question (x1,y1) and (x2,y2) are (-6,3) and (2,-5).
So the equation of line would be
[tex](y-3)=\frac{-5-3}{2+6}*(x+6)[/tex]
[tex]x+y+3=0[/tex]
b)
Given a point (-10,7)
by susbtituting in the equation we get
[tex]-10+7+3=0[/tex]
As the point satisfies it lies on the line.
