Respuesta :
Y=-1
Move all terms containing x to the left side of the equation.
Subtract 3x from both sides of the equation.
2x-3x=−5
Subtract 3x from 2x
−x=-5
Multiply each term in -x=−5 by −1
Multiply each term in −x=−5 by −1
(-x) ⋅ -1=(-5) ⋅-1
X=(-5) ⋅-1
multiple -5 by -1
X=5
Since x=5 is a vertical line, the slope is undefined.
Undefined
The equation of a perpendicular line to
x=5 must have a slope that is the negative reciprocal of the original slope.
M perpendicular = -1/∞
The negative reciprocal of ∞ is 0
M perpendicular is 0
Since the slope for the perpendicular line is 0 ,the line is perpendicular to the y-axis. The equation of this line is of the form
y=c when c is any real number. The equation of the line at point (-2 ,1)
Y=-1
I hope you understand this
Move all terms containing x to the left side of the equation.
Subtract 3x from both sides of the equation.
2x-3x=−5
Subtract 3x from 2x
−x=-5
Multiply each term in -x=−5 by −1
Multiply each term in −x=−5 by −1
(-x) ⋅ -1=(-5) ⋅-1
X=(-5) ⋅-1
multiple -5 by -1
X=5
Since x=5 is a vertical line, the slope is undefined.
Undefined
The equation of a perpendicular line to
x=5 must have a slope that is the negative reciprocal of the original slope.
M perpendicular = -1/∞
The negative reciprocal of ∞ is 0
M perpendicular is 0
Since the slope for the perpendicular line is 0 ,the line is perpendicular to the y-axis. The equation of this line is of the form
y=c when c is any real number. The equation of the line at point (-2 ,1)
Y=-1
I hope you understand this
Answer:
Equation: y=-2/3x-[tex]2\frac{2}{3}[/tex]
Step-by-step explanation:
y=mx +b
2y=3x-5
y=1.5x-2.5
y=-2/3x+b
(m is the negative reciprocal)
-2= 2/3+b
b=-2[tex]\frac{2}{3}[/tex]
Equation: y=-2/3x-[tex]2\frac{2}{3}[/tex]