Question

characteristics: • Of all the games, 67% were at-home games. Denote this by H (the remaining were away games). • Of all the games, 30% were wins. Denote this by W (the remaining were losses). • Of the at-home games, 34% of games were wins. Of all the games__________

Answer 1

Answer:

$P(W\cap H)  = 22.8%$

Step-by-step explanation:

Given data:

variables deceleration follow as

H - Home - Games

W - Winning Games  

from the information we have

P(H) = 0.67

P(W)= 0.30

$P(W\mid H) = 0.34$

Need to calculate the percentage of games that win at home. i.e.

$P(W\cap H)$

we know that:

$P(W\mid H) = \frac{P(W\cap H)}{P(H)}$

$0.34 =\frac{P(W\cap H)}{0.67}$

therefore we have

$P(W\cap H) = 0.34\times 0.67$

                          = 0.228

$P(W\cap H)  = 22.8%$