Question

In pea plants, yellow seed color is dominant to green, and wrinkled seed texture is dominant to smooth. In a dihybrid cross between two heterozygous plants with yellow, round seeds, if the two alleles assort independently, what is/are the predicted phenotypic ratio(s) of the offspring?​

Answer 1

Answer:

The answer would be: 9 yellow and round: 3 green and round: 3 yellow and wrinkled: 1 green and wrinkled

Explanation:

Answer 2

In a Mendelian cross when individuals with two different traits producing alleles are crossed with one another with the observed trait then the cross is said to be a dihybrid cross.

The phenotypic ratio of the offspring is 3(yellow round) : 1 (green round).

The Dihybrid cross can be explained as:

In this cross, two different traits taken are seed colour and seed texture.

• Yellow dominant allele = Y
• Green recessive allele = y
• Wrinkled dominant allele = R
• Round recessive allele = r

The cross is shown in the attached image below.

• The self cross between heterozygous plants with yellow, round seeds (Yyrr)  will produce 16 offspring with different genotypes and phenotypes.

• There will be no yellow wrinkled or green wrinkled progeny as the allele for wrinkled (RR) is absent in the parent plant.

• Progenies of a yellow round will be 12 and a green round will be 4.

Thus, 3:1 will be the phenotypic ratio.

Learn more about dihybrid cross here:

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