Answer:
[tex]F_{c}[/tex]=2863.6 N
Explanation:
the force make the whole truck-car system with some acceleration a.
the force acting on the system is given below
F=([tex](m_{t}-+m_{c})*a[/tex]
the acceleration is as follows
a=F/([tex](m_{t}-+m_{c})
the resultant force acting on the car results inits movement with acceleration a.
F-[tex]F_{c}[/tex]=ma
substituting acceleration term
[tex]F_{c}[/tex]=( [tex](m_{t}*F)/([tex](m_{t}-+m_{c})*a[/tex]
[tex]F_{c}[/tex]=[tex]\frac{2100*4500}{2100+1200}[/tex]
[tex]F_{c}[/tex]=2863.6 N
the tension force T and the horizontal force Frt of the road are not relevant
The force of the car pushing on the truck = F ct, and force of the truck pushing on the car = F tc are relevant