Answer: [tex]-0.054 m/s^{2}[/tex]
Explanation:
The question in english is written below:
A truck travels along the road at a speed of 70 km/h. It encounters an obstacle and brakes for about 360 seconds until it stops. What is the average acceleration of the truck?
Average acceleration [tex]a_{ave}[/tex] is the variation of velocity [tex]\Delta V[/tex] over a specified period of time [tex]\Delta t[/tex]:
[tex]a_{ave}=\frac{\Delta V}{\Delta t}}[/tex]
Where:
[tex]\Delta V=V_{f}-V_{o}[/tex]
[tex]V_{o}=70 \frac{km}{h}\frac{1000 m}{1 km} \frac{1 h}{3600 s}=19.44 m/s[/tex] is the initial velocity
[tex]V_{f}=0 m/s [/tex] the final velocity
[tex]\Delta t=360 s[/tex]
Then:
[tex]a_{ave}=\frac{V_{f}-V_{o}}{\Delta t}}[/tex]
[tex]a_{ave}=\frac{0 m/s-19.44 m/s}{360 s}}[/tex]
Finally:
[tex]a_{ave}=-0.054 m/s^{2}[/tex] Note the negative sign in the acceleration indicates the truck was decreasing its velocity until it stopped.