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A steamer going downstream traveled the distance between two ports in 3 hours. The return trip took 3 hours 40 minutes. Find the speed of the water current if the speed of the steamer in still water is 18 mph.

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frika

Answer:

1.8 mph

Step-by-step explanation:

Speed of the steamer in still water is 18 mph.

Speed of the current = x mph.

1. The steamer going downstream traveled the distance between two ports in 3 hours. Traveling downstream the current "helps" the steamer, then the speed is 18 + x mph.

The distance traveled downstream = 3(18 + x) miles.

2. The steamer going upstream traveled the distance between two ports in 3 hours 40 minutes that is [tex]3\frac{2}{3}[/tex] hours. Traveling upstream the current "interferes" the steamer, then the speed is 18 - x mph.

The distance traveled upstream [tex]3\dfrac{2}{3}(18-x)[/tex] miles.

3. The distances are the same, so

[tex]3(18+x)=3\dfrac{2}{3}(18-x)[/tex]

Solve this equation:

[tex]3(18+x)=\dfrac{11}{3}(18-x)\\ \\9(18+x)=11(18-x)\\ \\162+9x=198-11x\\ \\9x+11x=198-162\\ \\20x=36\\ \\x=1.8\ mph[/tex]

Answer:

The speed of water current is 1.8 mph

Step-by-step explanation:

Given information;

The speed in traveling downstream [tex]=x+18[/tex]

The speed in travelling upstream [tex]=18-x[/tex]

The distance traveled upstream [tex]= speed \times time[/tex] taken.

So, the distance will be [tex]=3\frac{2}{3} (18-x)[/tex]

As the distance is same in both the travel .

Then, we can write:

[tex]3(x+18)=3\frac{2}{3}(18-x)\\[/tex]

On solving the above equation:

[tex]3(x+18)=(11/3)(18-x)\\162+9x=198-11x\\20x=198-162\\x=1.8[/tex]

Hence, the speed of water current is 1.8 mph

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