Question

Production rate for an assembled product = 47.5 units per hour. Total work content time = 32 minutes of direct manual labor. The line operates at 95% uptime. Ten workstations have two workers on opposite sides of the line so that both sides of the product can be worked on simultaneously. The remaining stations have one worker. Repositioning time lost by each worker is 0.2 min/cycle. It is known that the number of workers on the line is two more than the number required for perfect balance. Determine (a) number of workers, (b) number of workstations, (c) balancing efficiency, and (d) average manning level.

Answer 1

Answer:

number of workers = 34 worker

number of work station = 24 station

balance efficiency = 34.1 %

average manning level = 1.417

Explanation:

given data

Production rate = 47.5 units per hour = $\frac{47.5}{60}$ unit per min

work content time = 32 minutes

Repositioning time lost = 0.2 min/cycle

solution

we find first number of worker that is

Tc = $\frac{0.95}{\frac{47.5}{60}}$

Tc = 1.2 min

and we know time loss 0.2 min

so

Ts = 1.2 - 0.2 = 1 min

so for perfect balance

Eb = 1 and

w = minimum integer ≥ 32 × 1 × 1 = 32 worker

and 2 more worker then required perfect balance = 32 + 2 = 34 worker

and

number of workstation is

number of work station is  = $\frac{20}{2}$ + (34 - 20 )

number of work station = 24 station

and

balance efficiency is

balance efficiency = $\frac{32}{34}$ × 100

balance efficiency = 34.1 %

and

average manning level is

average manning level = $\frac{34}{24}$

average manning level = 1.417