Answer: 8.1%
Step-by-step explanation:
Given : [tex]\mu=63[/tex]
[tex]\sigma=5[/tex]
Let x be the random variable that represents the actual speeds of cars.
The speed limit on a road is 60 mph.
Using formula , [tex]z=\dfrac{x-\mu}{\sigma}[/tex], we have for x= 60+10=70
[tex]\dfrac{70-63}{5}=1.4[/tex]
Using z-table for right-tailed test value, The probability of cars exceed the speed limit by more than 10 mph will be
[tex]P(x>70)=P(z>1.4)=0.0807567\approx0.081=8.1\%[/tex]
Hence, the percentage of cars exceed the speed limit by more than 10 mph is 8.1%.