Answer:
The answer to your question is: 25 g of PbCl2
Explanation:
Data
NaCl = 25 g
PbCl₂ = ?
Pb(NO3)2 + 2 NaCl ⇒ PbCl2 + NaNO3
MW NaCl = 58.5 g
MW PbCl2 = 277 g
2(58.5 g) of NaCl ------------------------ 277 g of PbCl2
25 g of NaCl ------------------------ x
x = (25 x 277) / 117
x = 25 g