Respuesta :
Answer:
She has 10 quarters, 5 dimes & 7 nickles.
Step-by-step explanation:
Use N: Nickle, D: Dime, and Q: Quarter. / $3.35 can be expressed as 335 cents in this case
----
Use what we know for some equations:
N = D+2 since two more nickles than dimes
Q = N+3 since three more quarters than nickles.
----
Basic Equation: 10D + 5N + 25Q = 335
Substitution Equation: Q= (d+5) + 3 = D+5
Substitution: 5*(d+2)+10D+25*(d+5) = 335
Solve:
5d+10+10d+25d+125 = 335
(Collect the terms)
5d+10d+25d= 40d
10+125= 135
40d + 135 = 335
(Subtract 135 on both sides)
335 - 135 = 200
(What's left)
40D = 200
(Divide)
40/200 = 5
(So,)
D = 5
----
Therefore there are 5 Dimes
Let's use the two equations up top:
Nickles) N = D+2 / N = 5 + 2 = 7, Therefore 7 nickles
Quarters: Q = N + 3 / Q = 7 + 3 = 10 Quarters
----
You can add them together if you'd like to check.
10Q = $2.50
5D = $.50
7N = $.35
(Add them up)
2.50+.50+.35 = $3.35!
Answer:
Number of nickels: n
Number of dimes: d
Number of quarters: q
Given:
n=d+2 , two more nickels than dimes,
q=n+3, three more quarters than nickels
Value of n nickels is 5n cents
Value of d dimes is 10d cents
Value of q quarters is 25q cents
Total money is $3.35 which can also be expressed as 335 cents.
5n+10d+25q=335
since n=d+2 and q=n+3, by substitution we can say that q=(d+2)+3=d+5
Now take the value equation and substitute the two expressions for nickels and quarters in terms of dimes in place of the n and q variables:
5(d+2)+10d+25(d+5)=335
Distribute and collect terms:
5d+10+10d+25d+125
40d+135=335
Add -135 to both sides:
40d=200
Divide by 40:
d=5
so there are 5 dimes. that means that there are 5+2=7 nickels and 5+5=10 quarters.
Check the answer:
10 quarters is $2.50,
5 dimes is $.50,
7 nickels is $.35, and finally,
$2.50 plus $.50 plus $.35 = $3.35
~Hope this helps!!