Question

You and a friend are spending the weekend making up missed lab experiments. You are on to second - semester material and are studying the electrostatic interaction of two charges. You notice that two charges are exerting a certain force on one another. If the distance between two electric charges doubles, then the force they exert on each other changes by how much?
2 times as large
4 times as large
1/4 as large
1/2 as large

Answer 1

Answer:

$F'=\dfrac{F}{4}$

1/4 as large  

Explanation:

Lets take

q₁ and q₂ are the charge on the particle and d is the distance between them.

We know that electrostatics between two particle given as

$F=K\dfrac{q_1q_2}{d^2}$

When distance become double d'= 2 d

So new force F'

$F'=K\dfrac{q_1q_2}{d'^2}$

$F'=K\dfrac{q_1q_2}{(2d)^2}$

$F'=K\dfrac{q_1q_2}{4d^2}$

$F'=\dfrac{F}{4}$

It means that force will become one forth of initial force.

So answer is 1/4 as large .