The weights of bags filled by a machine are normally distributed with a standard deviation of 0.05 kg and a mean that can be set by the operator. At what level should the mean be set if it is required that only 1% of the bags weigh less than 10 kg?

Respuesta :

Answer:

[tex]\mu [/tex] = 10.1163 kg

Step-by-step explanation:

given data

σ = 0.05

x = 10

so we know here probability of x is 0.1 that is  less than 10

so here Z is -2.326 by the standard table

we have here 1% to left when Z is - 2.326

now we apply relation between Z and x that is

Z = [tex]\frac{x -\mu}{\sigma }[/tex]   .........1

put here value

-2.326 = [tex]\frac{10 - \mu }{0.05}[/tex]

[tex]\mu [/tex] = 10.1163 kg

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