Explanation:
It is given that,
Mass of the runner, m = 70 kg
Length of the tendon, l = 15 cm = 0.15 m
Area of cross section, [tex]A=110\ mm^2=0.00011\ m^2[/tex]
Part A,
Let the runner's Achilles tendon stretch if the force on it is 8.0 times his weight, F = 8 mg
Young's modulus for tendon is, [tex]Y=0.15\times 10^{10}\ N/m^2[/tex]
The formula of the Young modulus is given by :
[tex]Y=\dfrac{F/A}{\dfrac{\Delta L}{L}}[/tex]
[tex]0.15\times 10^{10}=\dfrac{8\times 70\times 9.8/0.00011}{\dfrac{\Delta L}{0.15}}[/tex]
[tex]\Delta L=0.0049\ m[/tex]
Part B,
The fraction of the tendon's length does this correspond is given by :
[tex]\dfrac{\Delta L}{L}=\dfrac{0.0049}{0.15}[/tex]
[tex]\dfrac{\Delta L}{L}=0.0326[/tex]
Hence, this is the required solution.