Answer:
39
Step-by-step explanation:
[tex]x,y-\text{numbers}\\\\\text{One number is 9 more than 3 times another:}\ x=3y+9\\\text{Their difference is equal to 29:}\ x-y=29\\\\\text{We have the system of equations}\\\\\left\{\begin{array}{ccc}x=3y+9&(1)\\x-y=29&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\(3y+9)-y=29\\3y+9-y=29\qquad\text{subtract 9 fro both sides}\\3y-y+9-9=29-9\qquad\text{combine like terms}\\2y=20\qquad\text{divide both sides by 2}\\\dfrac{2y}{2}=\dfrac{20}{2}\\y=10\\\\\text{Put it to (1):}\\x=3(10)+9\\x=30+9\\x=39[/tex]
