Answer:
a) 3.13 m/s
b) 2.8 m/s
c) 0.485 m
d) 2.8 m/s
Explanation:
a) PE @ A = KE @ B
mgh = ½ mv²
v = √(2gh)
v = √(2 × 9.8 m/s² × 0.50 m)
v = 3.13 m/s
b) PE @ A = KE @ C + Work done by friction
mgh = ½ mv² + Fd
mgh = ½ mv² + mgμd
gh = ½ v² + gμd
g (h − μd) = ½ v²
v = √(2g (h − μd))
v = √(2 × 9.8 m/s² (0.50 m − 0.1 × 1 m))
v = 2.8 m/s
c) KE @ C = EE
½ mv² = ½ kx²
mv² = kx²
x = v √(m / k)
x = (2.8 m/s) √(3 kg / 100 N/m)
x = 0.485 m
d) Since there's no friction between point C and the spring, the speed is the same as before.
v = 2.8 m/s