Answer:
[tex]Y = 2.27 \times 10^{10} N/m^2[/tex]
Explanation:
Natural length of the string is given as
[tex]L_o = 43 cm[/tex]
length of the string while block is hanging on it
[tex]L = 53 cm[/tex]
extension in length is given as
[tex]\Delta L = 10 cm[/tex]
now we have strain in the string is given as
[tex]strain = \frac{\Delta L}{L}[/tex]
[tex]strain = \frac{{10 cm}{43 cm}[/tex]
[tex]strain = 0.23[/tex]
similarly we will have cross-sectional area of the string is given as
[tex]A = 40 \times 10^{-6} m^2[/tex]
now the stress in the string is given as
[tex]Stress = \frac{T}{A}[/tex]
[tex]Stress = \frac{mg}{A}[/tex]
[tex]Stress = \frac{3.7 \times 9.81}{40 \times 10^{-6}}[/tex]
[tex]stress = 9.07 \times 10^5 N/m^2[/tex]
Now Young's Modulus is given as
[tex]Y = \frac{stress}{strain}[/tex]
[tex]Y = \frac{9.07 \times 10^5}{40\times 10^{-6}}[/tex]
[tex]Y = 2.27 \times 10^{10} N/m^2[/tex]