A block weighing 3.7 kg is suspended from the ceiling of a truck trailer by a hanging bungee cord. The cord has a cross-sectional area 40 mm2 and an unstretched length of 43 cm.
The truck begins stopped at a red light on a state highway. While stopped, the block hangs straight down to a distance 53 cm below the hook that attaches the bungee cord to the ceiling of the truck.

(a) What is the Young's modulus of the cord?

Respuesta :

Answer:

[tex]Y = 2.27 \times 10^{10} N/m^2[/tex]

Explanation:

Natural length of the string is given as

[tex]L_o = 43 cm[/tex]

length of the string while block is hanging on it

[tex]L = 53 cm[/tex]

extension in length is given as

[tex]\Delta L = 10 cm[/tex]

now we have strain in the string is given as

[tex]strain = \frac{\Delta L}{L}[/tex]

[tex]strain = \frac{{10 cm}{43 cm}[/tex]

[tex]strain = 0.23[/tex]

similarly we will have cross-sectional area of the string is given as

[tex]A = 40 \times 10^{-6} m^2[/tex]

now the stress in the string is given as

[tex]Stress = \frac{T}{A}[/tex]

[tex]Stress = \frac{mg}{A}[/tex]

[tex]Stress = \frac{3.7 \times 9.81}{40 \times 10^{-6}}[/tex]

[tex]stress = 9.07 \times 10^5 N/m^2[/tex]

Now Young's Modulus is given as

[tex]Y = \frac{stress}{strain}[/tex]

[tex]Y = \frac{9.07 \times 10^5}{40\times 10^{-6}}[/tex]

[tex]Y = 2.27 \times 10^{10} N/m^2[/tex]

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