Answer:
The mass of hydrogen gas is collected is 0.073 grams.
Explanation:
[tex]2H^+(aq)+Zn(s)\rightarrow H_2(g)+Zn^{2+}(aq)[/tex]
Volume of gas collected = V = 0.947 L
Temperature of the gas ,T= 25°C = 298.15 K
Total pressure of pressure of the gas = 743 mmHg
Vapor pressure of the water = 23.78 mmHg
Pressure of the gas = 743 mmHg - 23.78 mmHg =719.22 mmHg=0.9463 atm
1 atm = 760 mmHg
Moles of hydrogen gas = n
Using an ideal gas equation:
[tex]PV=nRT[/tex]
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{0.9463 atm\times 0.947 L}{0.0821 atm L/mol K\tmes 298.15 K}[/tex]
n = 0.03661 mol
Mass of 0.03661 moles of hydrogen gas = 0.03661 mol × 2 g/mol= 0.073 g