Question

A student performed a chemical reaction in which 46 grams of sodium and ___ grams of chlorine were combined to form 117 grams of table salt and heat. What is the mass of the chlorine in the reactants? (answer with a number)

Answer 1

Answer:

The answer to your question is: 71 g of Chlorine

Explanation:

Na = 46 g

Cl = ?

NaCl = 117 g

Equation

                      2 Na     +     Cl₂   ⇒   2 NaCl          

                      46g              X              117g

If we consider the law of conservation of matter, we know that the mass of the reactants equals the mass of the products, then

                    mass Na + mass Cl₂  = mass NaCl

                     46 g + X = 117

                     X = 117 - 46

                    x = 71 g of Chlorine        

Answer 2

The mass of chlorine required to form 117 g table salt has been 35 g.

The balanced chemical equation for the formation of table salt has been:

$\rm 2\;Na\;+\;Cl_2\;\rightarrow\;2\;NaCl$

According to the balanced chemical equation for the formation of 2 moles of table salt, 2 moles of sodium, and 1 mole of Cl has been required.

Computation for the mass of Chlorine required

The moles of a compound has been given as:

$\rm Moles=\dfrac{Mass}{Molar\;mass}$

The moles of Na available has been:

$\rm Moles\;Na=\dfrac{46}{23}\\Moles\;Na=2$

The available moles of Na have been 2 moles.

The moles of NaCl formed has been:

$\rm Moles\;NaCl=\dfrac{117}{58} \\Moles\;NaCl=2$

The moles of NaCl formed has been 2 moles.

Thus, the moles of Cl required to form 2 moles of table salt from 2 moles of Na has been 1 mole. The mass of 1 mole Cl has been 35 g.

Thus, the mass of chlorine required to form 117 g table salt has been 35 g.

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