Respuesta :
Answer:
The volume of CO₂ produced by this power plant is 3,466x10¹²L
Explanation:
To obtain the volume of CO₂ produced you must use ideal gas law:
V = nRT/P
Where n are moles, R is gas constant (0,082atmL/molK), T is temperature and P is pressure (1,00atm)
The moles of CO₂ are:
6x10⁶ tons CO₂×[tex]\frac{1x10^{6}g}{1ton}[/tex] ×[tex]\frac{1mol}{44,01g}[/tex] = 1,363x10¹¹ moles of CO₂
Temperature in Kelvin is:
37°C + 273,15 = 310,15 K
Thus, the volume of CO₂ produced by this power plant is:
[tex]V = 1,363x10^{11} mol*0,082atmL/molK*310,15K/1,00atm[/tex]
V = 3,466x10¹²L
I hope it helps!
Explanation:
Let us assume that pressure is 1 atm and temperature is [tex]37^{o}C[/tex].
Now, according to the ideal gas PV = nRT. Hence, number of moles will be calculated as follows.
n = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{6,350,293,180,000}{44.01}[/tex]
= [tex]1.443 \times 10^{11}[/tex] mol
Also, convert temperature into kelvin as follows.
(273 + 37) K
= 310 K
Hence, calculate the volume as follows.
PV = nRT
V = [tex]\frac{1.443 \times 10^{11} \times 0.0821 Latm/mol K \times 310 K}{1 atm}[/tex]
= [tex]3.67 \times 10^{12}[/tex] L
Thus, we can conclude that volume of carbon dioxide produced by this power plant is [tex]3.67 \times 10^{12}[/tex] L.