100 points!!! Please help!!!

Suppose the pendulum in the figure has a mass of 0.34 kg and is moving to the right at point b with a speed of 2.4 m/s. Air resistance is negligible.

Find the maximum angle the string makes with the vertical as the bob swings back and forth. Ignore air resistance.

100 points Please help Suppose the pendulum in the figure has a mass of 034 kg and is moving to the right at point b with a speed of 24 ms Air resistance is neg class=

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Answer:

41°

Explanation:

Kinetic energy at bottom = potential energy at top

½ mv² = mgh

½ v² = gh

h = v²/(2g)

h = (2.4 m/s)² / (2 × 9.8 m/s²)

h = 0.294 m

The pendulum rises to a height of  above the bottom.  To determine the angle, we need to use trigonometry (see attached diagram).

L − h = L cos θ

cos θ = (L − h) / L

cos θ = (1.2 − 0.294) / 1.2

θ = 41.0°

Rounded to two significant figures, the pendulum makes a maximum angle of 41° with the vertical.

Ver imagen MathPhys

The maximum angle the pendulum makes with the vertical is 41°.

The total energy of the pendulum = maximum kinetic energy (at mean position or bottom) = maximum potential energy (at the highest point)

½ mv² = mgh,  where h is the maximum height of point A from point B

h = L − Lcosθ,  where L = 1.2 m and θ is the maximum angle

½ v² = gh

h = v²/(2g)

h = (2.4 m/s)² / (2 × 9.8 m/s²)

h = 0.294 m

Now to calculate the value of the angle

h = L − Lcosθ

cos θ = (L − h) / L

cos θ = (1.2 − 0.294) / 1.2

θ = 41.0°

The pendulum makes a maximum angle of 41° with the vertical.

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