Answer:
a). Roger travel total a distance of 2070m
b). The average speed of the whole tip [tex]V_{p}[/tex]0.16025[tex]\frac{m}{s}[/tex]
Explanation:
[tex]V= \frac{x}{t} = \frac{450m}{2 hr} * \frac{1 hr}{3600 s} = \frac{450m}{7200 s}\\ V= \frac{450m}{7200s} =0.125 \\V= 0.0625 \frac{m}{s} \\[/tex]
a).
First trip 450m
Second trip :
[tex]V=\frac{x}{t} \\x=V*t \\x= 15 \frac{cm}{s} *3 hr\\x= 15 (\frac{cm}{s}*\frac{1m}{100 cm}) * 3 hr (\frac{3600s}{1hr})\\ x=0.15 \frac{m}{s} * 3600s\\x= 1620 m[/tex]
So final distance is
450m+1620m=2070m
b).
[tex]V_{p} = \frac{0.15 \frac{m}{s}+0.0625 \frac{m}{s} }{2} =0.10625 \frac{m}{s}[/tex]
The average speed is [tex]V_{p}[/tex]0.10625 [tex]\frac{m}{s}[/tex]