Question

Q 5.76: Three climbers, each with a mass of 65 kg, are tied together with ropes and ascend an icy slope at a 25o angle. Suddenly, the back climber slips, pulling the second climber down as well. The front climber attempts to stop the group, but they continue to slide, accelerating as they go. Calculate the ratio of the tensions between the first (the rope between the front climber and the second climber) and the second rope. 1.5

Answer 1

Answer:

Solved

Explanation:

Free body diagram has been attached

and FBD we can say that

tension in c and b will be higher as T_1 helps to keep both the person steady.

So, $T_1= m_b g sin\theta +m_a g sin\theta$

m_a=m_b=m_c= 65 kg and θ=25°

The term g×sinθ is the component of acceleration along the inclined surface

Similarly $T_2= m_a g sin\theta$

putting the value of θ and mass we get

T_2= 269.207 N

T_1= 538.41 N