Answer:
[tex]v_{1i} = 4.8 m/s[/tex]
[tex]v_{1f} = 3.51 m/s[/tex]
Explanation:
Since the collision is perfectly elastic collision so here we can use momentum conservation
[tex]m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}[/tex]
so we will have
[tex]129 v_{1i} + 0 = 129(-v_{1f}) + 831(1.29)[/tex]
[tex]v_{1i} + v_{1f} = 8.31[/tex]
also by elastic collision property we will have
[tex]1.29 + v_{1f} = v_{1i}[/tex]
now from above two equations we have
[tex]v_{1i} = 4.8 m/s[/tex]
[tex]v_{1f} = 3.51 m/s[/tex]