Question

On the first part of a trip to Carmel traveling on the​ freeway, Marge averaged 70 mph. On the rest of the​ trip, which was 25 mi longer than the first​ part, she averaged 60 mph. Find the total distance to Carmel if the second part of the trip took 30 minutes more than the first part.

Answer 1

Answer:

95 miles

Step-by-step explanation:

Let the distance traveled in first part be x

Speed = 70 mph

So, Time = $\frac{Distance}{Speed} =\frac{x}{70}$

We are given that  On the rest of the​ trip, which was 25 mi longer than the first​ part, she averaged 60 mph.

So, distance in second part = x+25

Speed = 60

So, Time = $\frac{Distance}{Speed} =\frac{x+25}{60}$

Now we are given that he second part of the trip took 30 minutes more than the first part.

$\frac{x}{70}+\frac{30}{60}=\frac{x+25}{60}$

$\frac{30}{60}=\frac{x+25}{60}-\frac{x}{70}$

$\frac{1}{2}=\frac{x+175}{420}$

$210=x+175$

$210 -175 = x$

$35 = x$

So, total distance = distance in first part+ distance in second part = x+x+25=35+35+25= 95

Hence the total distance is 95 miles