Answer:
The needed sample size is approximately 61.46 individuals.
Step-by-step explanation:
We can use the following formula to obtain the sample size:
[tex]n_0 = \big(\frac{z_{1 - \frac{\alpha}{2}}S_d}{e} \big)[/tex]
Where [tex]S_d[/tex] is the standard deviation, [tex]{z_{1 - \frac{\alpha}{2}[/tex] is the quantile of the normal distribution with area of [tex]1 - \frac{\alpha}{2}[/tex] and [tex]e[/tex] is the acceptable error.
[tex]n_0 = \big(\frac{1.96\times20}{5} \big) \approx 61.46[/tex]
We would need a sample size of 62 individuals.