Question

In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, but it is larger and softer. In one hit, the ball leaves the bat at 12 m/s after being in contact with the bat for 2.0 ms . Assume constant acceleration during the hit. What is the acceleration of the ball?

Answer 1

Answer:

$a=6000m/s^2$

Explanation:

To solve this problem we will use the equation for accelerated motion (which is the definition of acceleration):

$a=\frac{v_f-v_i}{t}$

For our case we have a ball departing from rest, achieving a final velocity of 12m/s in a time equal to 2ms=0.002s, so substituting our values we have:

$a=\frac{v_f-v_i}{t}=\frac{(12m/s)-(0m/s)}{(0.002s)}=6000m/s^2$