Answer:0.323
Explanation:
mass of spherical shell=1.95 kg
inclination [tex]\theta =39^{\circ}[/tex]
Friction[tex](f_r)[/tex] will oppose the motion of shell
[tex]mgsin\theta -f_r=ma[/tex]
where a=acceleration
a is given by
[tex]a=\frac{gsin\theta }{1+\frac{I}{mr^2}}[/tex]
I=moment of inertia [tex]=\fac{2mr^2}{3}[/tex]
[tex]a=\frac{3gsin\theta }{5}[/tex]
[tex]f_r=mg\sin \theta -\frac{3mgsin\theta }{5}[/tex]
[tex]f_r=\frac{2mgsin\theta }{5}[/tex]
and [tex]f_r=\mu N[/tex]
[tex]f_r=\mu mg\cos \theta [/tex]
[tex]\mu mg\cos \theta =\frac{2mgsin\theta }{5}[/tex]
[tex]\mu =\frac{2}{5}\times \tan \theta [/tex]
[tex]\mu =0.323[/tex]