Answer:
The volume of the original solution is 10.00 mL.
Explanation:
We have a concentrated solution of C₁ = 0.0880 M and we want to prepare 100.0 mL (V₂) of a dilute one of C₂ = 0.0088 M. To calculate the volume of solution 1 (V₁) to be diluted we use the dilution rule.
C₁.V₁=C₂.V₂
[tex]V_{1}=\frac{C_{2}.V_{2}}{C_{1}} =\frac{0.0088M \times 100.0mL }{0.0880M} =10.00mL[/tex]