Explanation:
It is given that,
Let m is the mass of the object that is hung from a vertical spring of unknown spring constant k. When the spring is stretched by 17 cm, the object executes SHM. Let T is the period of oscillation that is given by :
[tex]T=2\pi \sqrt{\dfrac{m}{k}}[/tex].............(1)
The gravitational force is balanced by the force of spring at equilibrium as :
[tex]mg=kx[/tex]
[tex]\dfrac{m}{k}=\dfrac{x}{g}[/tex]
So, equation (1) becomes :
[tex]T=2\pi \sqrt{\dfrac{x}{g}}[/tex]
x = 17 cm = 0.17 m
[tex]T=2\pi \sqrt{\dfrac{0.17\ m}{9.8\ m/s^2}}[/tex]
T = 0.82 seconds
So, the period of this oscillation is 0.82 seconds. Hence, this is the required solution.