Answer:
[tex]F = 505.13 N[/tex]
Yes it is better to pull the rope rather than push it
Explanation:
Let the force is applied at an angle of 60 degree
so we will have net vertical force on the crate is given as
[tex]F_n + Fsin60 = mg[/tex]
here we know
[tex]m = 180 lb[/tex]
[tex]m = 81.65 kg[/tex]
[tex]F_n = 81.65(9.81) - Fsin60[/tex]
[tex]F_n = 801 - 0.866 F[/tex]
now friction force on the crate is given as
[tex]F_x = \mu F_n[/tex]
[tex]Fcos60 = 0.7(801 - 0.866 F)[/tex]
[tex]0.5F + 0.61F = 560.7[/tex]
[tex]F = 505.13 N[/tex]
Yes it is better to pull the rope rather than push it