Answer:
5.9°C
Explanation:
Summit height = 4200 m = 4.2 km
Ground height = 900 m = 0.9 km
Height above the ground = 4.2 km - 0.9 km = 3.3 km
the average or normal lapse rate is expected to be 6.4°C/km.
the temperature at summit of mountain would be =
= Temperature at ground - [(4.2 km - 0.9 km) × lapse rate]
= 27° - [ 3.3 × 6.4° ]
= 27° - 21.12 °
= 5.88°C
≈ 5.9°C
Hence, the air temperature at the summit is 5.9°C