Answer:
maximum acceleration is 6.86 m / s²
Explanation:
We use Newton's second law for each axis
X axis
Fr = ma
Axis y
N-W = O
N = mg
The equation for the force of friction is
fr = μ N
The maximum value of the friction force occurs with the static coefficient
fr = 0.7 0.47 9.8
fr = 3,224 N
a = fr / m
a = 3,224 / 0.47
a = 6.86 m / s²
If the vehicle exceeds this acceleration the cup begins to slide and the friction force is reduced because its efficient changes to dynamic