Answer: [tex]a_{2}=\frac{m_{1}}{m_{2}} a_{1}[/tex]
Explanation:
The rest of the question is below:
Find a2, the magnitude of the centripetal acceleration of the star with mass m2.
Assuming both stars are describing a uniform circular motion, their acceleration vector is directed towards the center of mass of the system (that's why it's called centripetal acceleration).
Now, according to Newton's 2nd law, the force [tex]F[/tex] is directly proportional and in the same direction as the acceleration.
For [tex]m_{1}[/tex]:
[tex]F_{1}=m_{1}a_{1}[/tex]
For [tex]m_{2}[/tex]:
[tex]F_{2}=m_{2}a_{2}[/tex]
If the centripetal force is the same for both stars:
[tex]F_{1}=F_{2}[/tex]
[tex]m_{1}a_{1}=m_{2}a_{2}[/tex]
Isolating [tex]a_{2}[/tex]:
[tex]a_{2}=\frac{m_{1}}{m_{2}} a_{1}[/tex]