Answer:
This is strong evidence that more than 2% get damaged
Step-by-step explanation:
The company goal is to keep the proportion of damaged machines below 2%
[tex]H_o: p = 0.02[/tex]
[tex]H_a: p > 0.02[/tex]
One day an inspector randomly checks 66 washers and finds that 6 of them have scratches or dents
So, x = 6
n = 66
[tex]\widehat{p}=\frac{x}{n}[/tex]
[tex]\widehat{p}=\frac{6}{66}[/tex]
Formula : [tex]z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]z=\frac{\frac{6}{66}-0.02}{\sqrt{\frac{0.02(1-0.02)}{66}}}[/tex]
[tex]z=4.114[/tex]
So, the value of test statistic is 4.114
2) What is the P-value of the test statistic?
So, p value using calculator = .00002
p value < α
So, we accept the alternate hypothesis
So, This is strong evidence that more than 2% get damaged