Please help me out with this!
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Answer:
y = - 8x + 12
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (10, - 68)
m = [tex]\frac{-68-4}{10-1}[/tex] = [tex]\frac{-72}{9}[/tex] = - 8, thus
y = - 8x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (1, 4), then
4 = - 8 + c ⇒ c = 4 + 8 = 12
y = - 8x + 12 ← equation of trend line
Answer:
y = -8x + 12.
Step-by-step explanation:
Using the slope formula: slope m = (y2-y1) / (x2-x1) where (x1,y1) and (x2,y2) are points on the line.
The slope of the line is (-68-4) / (10 - 1)
= - 72 / 9
= -8.
Now we use the slope-form of the straight line to get the required equation:
y - y1 = m(x - x1) where m is the slope and (x1, y1) is a point on the line:
y - 4 = -8(x - 1)
y = -8x + 8 + 4
y = -8x + 12. (answer).