Answer:
a= 1.81 m/s²
Explanation:
Ratio of the weights on both surfaces can be calculated as,
[tex]\frac{W_{a} }{W_{E} }[/tex]=[tex]\frac{ma}{mg}[/tex]
Here;
Wa is the weight on the asteroid, [tex]W_{E}[/tex] is weight on earth,
m is mass of pack, a is acceleration due to an asteroid and
g is acceleration due to gravity.
Rearrange above equation for a,
a=g ([tex]\frac{Wa}{W_{E} }[/tex])
Substitute 3.24 N for Wa, 17.5 N for [tex]W_{E}[/tex],
9.81 m/s² for g in the above equation,
a= 9.81([tex]\frac{3.24}{17.5}[/tex])
a= 1.81 m/s²