Respuesta :
Let 6x-3y=3 be equation 1 and -2x +6y=14 be equation 2.
Take 2 common from eq 2 let the optioned eq be equation number 3.
And solve eq number 1 and 3.
Take 2 common from eq 2 let the optioned eq be equation number 3.
And solve eq number 1 and 3.
Answer:
Solving the system of equations using elimination involves eliminating one variable by adding or subtracting the equations. Elimination method is as follows:
5)2x + 6y = -12)
2(5x - 5y = 10
10x - 30y = -60
10x - 10y = 20
We subtract the equations eliminating the 10x term.
40y = -80
y = -2
x = (10 + (-2)5) / 5
x=0
Hope this helps!