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Answer : The number of molecules of gas in a sample are [tex]1.21\times 10^{22}[/tex]
Explanation :
First we have to calculate the moles of carbon dioxide gas in a sample.
[tex]PV=nRT[/tex]
where,
P = pressure of carbon dioxide gas = 0.955 atm
V = volume of carbon dioxide gas = 500.0 mL = 0.500 L
T = temperature of carbon dioxide gas = [tex]15.9^oC=273+15.9=288.9K[/tex]
n = number of moles of carbon dioxide gas = ?
R = gas constant = 0.0821 L.atm/mol.K
Now put all the given values in the ideal gas equation, we get:
[tex](0.955atm)\times (0.500L)=n\times (0.0821 L.atm/mol.K)\times (288.9K)[/tex]
[tex]n=0.0201mol[/tex]
Now we have to calculate the number of molecules of gas in a sample.
As we know that, 1 mole of gas contains [tex]6.022\times 10^{23}[/tex] number of molecules of gas.
As, 1 mole of carbon dioxide gas contains [tex]6.022\times 10^{23}[/tex] number of molecules of gas.
So, 0.0201 mole of carbon dioxide gas contains [tex]0.0201\times 6.022\times 10^{23}=1.21\times 10^{22}[/tex] number of molecules of gas.
Therefore, the number of molecules of gas in a sample are [tex]1.21\times 10^{22}[/tex]