Question

A worker drops a wrench from the top of a tower 80m tall. What is the velocity when the
wrench strikes the ground?​

Answer 1

Answer:

39.6 m/s

Explanation:

Taking down to be positive:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

Δy = 80 m

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (80 m)

v = 39.6 m/s

Answer 2

The velocity of the wrench is 39.6 m/s.

Explanation:

Given that,

Height of tower = 80 m

We need to calculate the velocity of the wrench when the  wrench strikes the ground

Using the third kinematics equation

$v^2=u^2+2gs$

Where,

v = final velocity

u = initial velocity

g = acceleration due to gravity

s = traveling distance

Put the value into the formula

$v^2=0+2\times9.8\times80$

$v=\sqrt(2\times9.8\times80)$

$v=39.6 m/s$

Hence, The velocity of the wrench is 39.6 m/s.

Reference :

https://brainly.com/question/14359007