Respuesta :

Answer:

The FSBL is 100.05 dB

Solution:

As per the question:

Frequency, f = 2.4 GHz = [tex]2.4\times 10^{9}[/tex]

Now, we know that to calculate FSBL, i.e., Free Space Path Loss in dB, we use:

[tex]FSBL(in dB) = 10log_{10}(\frac{4\pifd}{c})^{2}[/tex]

where

d = 1 km = 1000

c = [tex]3\times 10^{8} m/s[/tex]

[tex]FSBL(in dB) = 20log_{10}\frac{4\pifd}{c} = 20log_{10}(fd) + 20log_{10}(\frac{4\pi}{c})[/tex]

[tex]FSBL(in dB) = 20log_{10}(f) + 20log_{10}(d) + 20log_{10}(\frac{4\pi}{c})[/tex]

[tex]FSBL(in dB) = 20log_{10}(2.4\times 10^{9}) + 20log_{10}(10^{3}) + 20log_{10}(\frac{4\pi}{3\times 10^{8}})[/tex]

[tex]FSBL(in dB) = 20\times 9.3802 + 20\times 3 - 147.55 = 100.05 dB[/tex]