Answer:
5.0 × 10⁴ g of CO₂
Explanation:
First, we write the balanced equation for the combustion of methane.
CH₄ + 1.5 O₂ ⇄ CO₂ + H₂O
Now, we can establish the following relations:
Using proportions,
[tex]10^{9} J.\frac{10^{3}gCH_{4} }{55 \times 10^{6} J } .\frac{44gCO_{2}}{16gCH_{4}} =5.0 \times 10^{4} g CO_{2}[/tex]