well, we know the actual distance is 612, however the estimate is 735, is off by 735 - 612 = 123.
now if we take 612 to be the 100%, what is 123 off of it in percentage?
[tex]\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 612&100\\ 123&x \end{array}\implies \cfrac{612}{123}=\cfrac{100}{x}\implies \cfrac{204}{41}=\cfrac{100}{x}\implies 204x=4100 \\\\\\ x = \cfrac{4100}{204}\implies x = \cfrac{1025}{51}\implies x \approx 20.098[/tex]