Answer:
a) 56 milimoles.
b) 121 milimoles.
c) 0,199 milimoles.
Explanation:
The molarity (M) is an unit of chemical concentration that relates moles of solute per L of solution.
Parts per million (ppm) is another unit of chemical concentration that relates mg of solute per kg of solution.
One mole are 1000 milimoles.
a) 175 mL of 0,320 M HClO₄ are:
0,175L×[tex]\frac{0,320mol}{L}[/tex] = 0,056 moles of HClO₄. That are 56 milimoles.
b) 15 L of 8,05x10⁻³ M K₂CrO₄ are:
15L×[tex]\frac{8,05x10^{-3}mol}{L}[/tex] = 0,121 moles of K₂CrO₄. That are 121 milimoles.
c) 5,00L≡ 5,00kg of an aqueous solution 6,75 ppm AgNO₃ are:
5,00kg×[tex]\frac{6,75mg}{kg}[/tex]×[tex]\frac{1milimole}{169,87mg}[/tex] = 0,199 milimoles.
I hope it helps!
a) 56 milimoles of solute
b) 121 milimoles of solute
c) 0.199 milimoles of solute
It is a measure of the concentration of a solute in a solution, in terms of amount of substance per unit volume of solution.
Parts per million (ppm) is another unit of chemical concentration that relates mg of solute per kg of solution.
[tex]1\text{ mol}=1000\text{ millimoles}[/tex]
a) 175 mL of 0.320 M HClO₄ are:
[tex]0.175L*\frac{0.320mol}{L} = 56\text{ millimoles}[/tex]
b) 15 L of 8.05 * 10⁻³ M K₂CrO₄ are:
[tex]15L*\frac{8.05*10^{-3}mol}{L} = 121 \text{ millimoles}[/tex]
c) 5,00L≡ 5,00kg of an aqueous solution 6,75 ppm AgNO₃ are:
[tex]5.00kg*\frac{6.75mg}{kg}*\frac{1 \text{ millimole}}{169.87mg} = 0.199 \text{ millimoles}[/tex]
Find more information about Molarity here:
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