Question

In the laboratory, a student dilutes 18.2 mL of a 6.88 M perchloric acid solution to a total volume of 300. mL. What is the concentration of the diluted solution?______M

Answer 1

Answer:

0.4443

Explanation:

Considering

$Molarity_{1}\times Volume_{1}=Molarity_{2}\times Volume_{2}$

Given  that:

$Molarity_{1}=6.88\ M$

$Volume_{1}=18.2\ mL$

Total volume = 300 mL

$Volume_{2}=300-18.2\ mL=281.8\ mL$

$Molarity_{2}=?$

So,  

$6.88\times 18.2=Molarity_{2}\times 281.8$

$Molarity_{2}=0.4443\ M$