Question

What is the pressure of 0.38 mol of gas if it has a volume of 9.614 L and a temperature of 255 K. The gas constant is i (Hint: don't worry about what a "pas constant" is just make the units work! This is a conversion factor do NOT plug any numbers into it. Use it to cancel units) ball Park 0.8-0.9 atm

Answer 1

Answer:

The answer to your question is: P = 0.827 atm

Explanation:

Data

n = 0.38 mol

volume = 9,614 l

temperature = 255 °K

R = 0.08206 atm L/mol°K

Formula

              PV = nRT

             P = nRT / V

Process

              $P = \frac{(0.38)(0.08206)((255)}{(9.614)}$

                     $P = \frac{7.952}{9.614}$

                     $P = 0.827 atm$