Question

How many carbon atoms are in 8.44 mL of C3H6O? 1 mole = 6.02 x 1023 atoms 1 mL = 0.898 g

The answer has to be in the correct significant figures. Not sure how to do this.

Answer 1

Answer:

$2.36\times 10^{23}\ atoms$

Explanation:

Given Volume = 8.44 mL

Also, 1 mL = 0.898 g

SO, 8.44 mL = 0.898*8.44 g = 7.57912 g

Moles of $C3H6O$ can be calculated as:

Molar mass of $C3H6O$ = 58.08 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{7.57912\ g}{58.08\ g/mol}$

$Moles\= 0.1305\ mol$

1 mole of $C3H6O$ contains 3 moles of carbon.

Thus, 0.1305 mole of $C3H6O$ contains 3*0.1305 moles of carbon.

Moles of carbon = 0.3915 moles

Also,

1 mole = $6.023\times 10^{23}\ atoms$

So, 0.3915 moles = $0.3915\times 6.023\times 10^{23}\ atoms=2.36\times 10^{23}\ atoms$