Respuesta :
Explanation:
The given data is as follows.
Molarity = 0.1 M, Area = 7.2 [tex]cm^{2}[/tex]
Resistance = 12.553 ohm, Length = 3.6 cm
As it is known that relation between resistance, length and area is as follows.
R = [tex]\rho \frac{l}{A}[/tex]
and, [tex]\frac{1}{R} = \frac{1}{\rho} \times \frac{A}{l}[/tex]
[tex]k = c \times x[/tex]
where, k = specific conductivity
c = conductance
x = cell constant
Therefore, value of c = [tex]\frac{1}{R}[/tex] = [tex]\frac{1}{12.553}[/tex] = 0.0796 per ohm
x = [tex]\frac{l}{A}[/tex] = [tex]\frac{3.6 cm}{7.2 cm^{2}}[/tex]
= 0.5 per cm
Hence, calculate the value of specific conductivity as follows.
[tex]k = c \times x[/tex]
= [tex]0.0796 per ohm \times 0.5 per cm[/tex]
= 0.0398 per ohm per cm
Relation between molar ionic conductivity and specific conductivity is as follows.
[tex]\lambda_{m} = \frac{k \times 1000}{M}[/tex]
= [tex]\frac{0.0398 \text{per ohm per cm} \times 1000}{0.1 M}[/tex]
= 398 [tex]\Omega^{-1} cm^{2} mol^{-1}[/tex]
Also, [tex]\Omega^{-1}[/tex] = Siemen
[tex]\lambda_{m} = 398 S cm^{2} mol^{-1}[/tex]
thus, we can conclude that value of molar ionic conductivity of given hydrogen ions is [tex]398 S cm^{2} mol^{-1}[/tex].
