Question

In parallelogram defg,, DH = x+3 HF= 3y GH=3x-3 and HE =5y + 4

Answer 1

Answer:

The value of x and y is 9 and 4 units

Solution:

We have,  

DH = x+3; HF= 3y and GH=3x-3; HE =5y + 4

For parallelogram, we know that,

DH=HF

So, $(x+3)=3 y\Rightarrow x=(3 y-3)$--------- (i)

Again, GH = HE

So, $3x-3 = 5y +4$

$\Rightarrow3 x=5 y+4+3$

$x = \frac{(5y+7)}{3}$ ………. (ii)

Now equating both (i) and (ii) we get,

$\Rightarrow3 y-3=\frac{5 y+7}{3}$

$\Rightarrow3\times(3y-3) = 5y+7$

$\Rightarrow9y - 9 = 5y +7$

$\Rightarrow9y-5y=7+9$

$\Rightarrow4y = 16$

$\Rightarrow y = 4$

So the value of $x = 3\times4 -3 = 9$

The value of x and y is 9 and 4  units

Answer 2

Answer:

9 and 4

Step-by-step explanation:

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